题目内容

如图,小明在楼上点A处观察旗杆BC,测得旗杆顶部B的仰角为30°,测得旗杆底部C的俯角为60°,已知点A距地面的高AD为12m.求旗杆的高度.

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                             

       

答案:解:过点A作AE⊥BC,垂足为E,得矩形ADCE,∴CE=AD=12.

     PC=PA·cos∠APC=30…………………………………2分

     在Rt△PCB中,………………………1分    …………………………………2分

答:当渔船位于P南偏东45°方向时,渔船与P的距离是30海里。……1分

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