题目内容
若x2-y2-x+y=(x-y)•A,则A=______.
原式=(x2-y2)-(x-y),
=(x-y)(x+y)-(x-y),
=(x-y)(x+y-1).
因此A=x+y-1.
=(x-y)(x+y)-(x-y),
=(x-y)(x+y-1).
因此A=x+y-1.
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