题目内容
计算:| x2+1 |
| x2-1 |
| x-2 |
| x-1 |
| x-2 |
| x |
分析:解题关键是先把除法统一为乘法,化简后再算减法.再通分,然后合并同类项再化简即可.
解答:解:
-
÷
=
-
×
=
-
=
-
=
=
=-
故答案为-
.
| x2+1 |
| x2-1 |
| x-2 |
| x-1 |
| x-2 |
| x |
=
| x2+1 |
| x2-1 |
| x-2 |
| x-1 |
| x |
| x-2 |
=
| x2+1 |
| x2-1 |
| x |
| x-1 |
=
| x2+1 |
| (x+1)(x-1) |
| x2+x |
| (x+1)(x-1) |
=
| x2+1-x2-x |
| (x+1)(x-1) |
=
| 1-x |
| (x+1)(x-1) |
=-
| 1 |
| x+1 |
故答案为-
| 1 |
| x+1 |
点评:本题考查分式的混合运算,关键是通分,合并同类项,注意混合运算的运算顺序.
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