题目内容
(x+1)(x+2)=2x+4,
(x+1)(x+2)﹣2(x+2)=0,(x+2)(x+1﹣2)=0,
x+2=0,x+1﹣2=0, x1=﹣2,x2=1.
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若(x+1)2+
=0,则x+y的值为( )
| 2y-1 |
| A、-1 | ||
B、
| ||
| C、0 | ||
D、-
|
题目内容
(x+1)(x+2)=2x+4,
(x+1)(x+2)﹣2(x+2)=0,(x+2)(x+1﹣2)=0,
x+2=0,x+1﹣2=0, x1=﹣2,x2=1.
| 2y-1 |
| A、-1 | ||
B、
| ||
| C、0 | ||
D、-
|