题目内容
先化简,再求值:(
-
)÷
,其中x=
-4.
| 3 |
| x-2 |
| 1 |
| x+2 |
| 2 |
| x2-4 |
| 2 |
原式=
×
=x+4;
∵x=
-4;
∴原式=x+4=
.
| 2x+8 |
| (x-2)(x+2) |
| (x-2)(x+2) |
| 2 |
∵x=
| 2 |
∴原式=x+4=
| 2 |
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题目内容
| 3 |
| x-2 |
| 1 |
| x+2 |
| 2 |
| x2-4 |
| 2 |
| 2x+8 |
| (x-2)(x+2) |
| (x-2)(x+2) |
| 2 |
| 2 |
| 2 |