题目内容
计算:20022-20012+20002-19992+19982-…+22-12.
原式=(2002+2001)+(2000+1999)+…(2+1)(2-1)
=2002+2001+2000+1999+1998+…+2+1
=
=2005003.
=2002+2001+2000+1999+1998+…+2+1
=
| (2002+1)×2002 |
| 2 |
=2005003.
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| (2002+1)×2002 |
| 2 |