题目内容
(2012•珠海)先化简,再求值:(
-
)÷(x+1),其中x=
.
| x |
| x-1 |
| 1 |
| x2-x |
| 2 |
分析:线将括号内的分式通分,进行加减后再算除法,计算时,要将除法转化为乘法.
解答:解:原式=[
-
]×
=
×
=
,
当x=
时,
原式=
=
.
| x2 |
| x(x-1) |
| 1 |
| x(x-1) |
| 1 |
| x+1 |
=
| (x-1)(x+1) |
| x(x-1) |
| 1 |
| x+1 |
=
| 1 |
| x |
当x=
| 2 |
原式=
| 1 | ||
|
| ||
| 2 |
点评:本题考查的是分式的化简求值,熟知分式混合运算的法则是解答此题的关键.
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