题目内容
计算:(1)8+(-| 1 |
| 4 |
(2)(-12)×|-
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
(3)(-60)×(
| 2 |
| 3 |
| 11 |
| 12 |
| 14 |
| 15 |
(4)比较大小:-
| 9 |
| 7 |
| 6 |
| 5 |
(5)(-4)×(-
| 5 |
| 7 |
| 4 |
| 7 |
| 1 |
| 2 |
(6)(-1)3-(1-
| 1 |
| 2 |
分析:运用有理数的运算法则,先算乘方后算乘除,以及负数比较大小,绝对值大的反而越小,可以比较出大小.
解答:解:(1)8+(-
)-5-(-0.25),
=8-
-5+0.25,
=3;
(2)(-12)×|-
|+(-
)2÷(-
)3×(-1)2010,
=(-12)×
+
÷(-
)×1,
=-4-
,
=- 4
;
(3)(-60)×(
-
-
)+(-2)3,
=(-60)×
-
×(-60)-
×(-60)-8,
=63;
(4)比较大小:-
与-
,
利用负数的绝对值越大反而越小,可得:-
<-
;
(5)(-4)×(-
)÷(-
)-(
)3,
=
×(-
)-
,
=-5-
,
=-5
;
(6)(-1)3-(1-
)÷3×[2-(-3)2],
=-1-
×
×(-7),
=-1+
,
=
.
| 1 |
| 4 |
=8-
| 1 |
| 4 |
=3;
(2)(-12)×|-
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
=(-12)×
| 1 |
| 3 |
| 1 |
| 16 |
| 1 |
| 8 |
=-4-
| 1 |
| 2 |
=- 4
| 1 |
| 2 |
(3)(-60)×(
| 2 |
| 3 |
| 11 |
| 12 |
| 14 |
| 15 |
=(-60)×
| 2 |
| 3 |
| 11 |
| 12 |
| 14 |
| 15 |
=63;
(4)比较大小:-
| 9 |
| 7 |
| 6 |
| 5 |
利用负数的绝对值越大反而越小,可得:-
| 9 |
| 7 |
| 6 |
| 5 |
(5)(-4)×(-
| 5 |
| 7 |
| 4 |
| 7 |
| 1 |
| 2 |
=
| 20 |
| 7 |
| 7 |
| 4 |
| 1 |
| 8 |
=-5-
| 1 |
| 8 |
=-5
| 1 |
| 8 |
(6)(-1)3-(1-
| 1 |
| 2 |
=-1-
| 1 |
| 2 |
| 1 |
| 3 |
=-1+
| 7 |
| 6 |
=
| 1 |
| 6 |
点评:此题主要考查了有理数的混合运算,应注意运算顺序,以及负数的比较大小.
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