题目内容
先化简下列式子:
(x+y)2+
(x+y)+
(x+y)-
(x+y)2-
(x+y).再计算当x+y=-2时原式的值.
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原式=
(x+y)2-
(x+y),
当x+y=-2时,原式=
+1=
.
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当x+y=-2时,原式=
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