题目内容
(1)解方程:
-
=1
(2)先化简
-
再任选一个适当的x值代入求值.
| x+1 |
| x-1 |
| 4 |
| x2-1 |
(2)先化简
| x2+2x+1 |
| x2-1 |
| x |
| x-1 |
(1)分式方程去分母得:(x+1)2-4=x2-1,
去括号得:x2+2x+1-4=x2-1,
解得:x=1,
经检验x=1是增根,原分式方程无解;
(2)原式=
=
=
,
当x=2时,原式=1.
去括号得:x2+2x+1-4=x2-1,
解得:x=1,
经检验x=1是增根,原分式方程无解;
(2)原式=
| (x+1)2-x(x+1) |
| (x+1)(x-1) |
=
| x+1 |
| (x+1)(x-1) |
=
| 1 |
| x-1 |
当x=2时,原式=1.
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