题目内容
已知
=
=
，则
=
．
| x |
| 5 |
| y |
| 3 |
| z |
| 4 |
| 2x+y-z |
| x+3y+z |
| 1 |
| 2 |
| 1 |
| 2 |
分析：首先设
=
=
=k，即可得x=5k，y=3k，z=4k，然后代入
，即可求得答案．
| x |
| 5 |
| y |
| 3 |
| z |
| 4 |
| 2x+y-z |
| x+3y+z |
解答：解：设
=
=
=k，
∴x=5k，y=3k，z=4k，
∴
=
=
=
．
故答案为：
．
| x |
| 5 |
| y |
| 3 |
| z |
| 4 |
∴x=5k，y=3k，z=4k，
∴
| 2x+y-z |
| x+3y+z |
| 10k+3k-4k |
| 5k+9k+4k |
| 9k |
| 18k |
| 1 |
| 2 |
故答案为：
| 1 |
| 2 |
点评：此题考查了比例的性质．注意设
=
=
=k，得到x=5k，y=3k，z=4k，是解此题的关键．
| x |
| 5 |
| y |
| 3 |
| z |
| 4 |
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