题目内容
计算或化简:
(1)
-
(
+2);
(2)
+
-(
-1)0+(-2)-2-3
;
(3)(6
-2x
)÷3
;
(4)已知:x=
,求x2-x+1的值.
(1)
| 8 |
| 2 |
| 2 |
(2)
| 2 | ||
|
| 27 |
| 3 |
|
(3)(6
|
|
| x |
(4)已知:x=
| 2 | ||
|
(1)
-
(
+2),
=2
-2-2
,
=-2;
(2)
+
-(
-1)0+(-2)-2-3
,
=
+1+3
-1+
-
,
=3
+
;
(3)(6
-2x
)÷3
,
=(3
-2
)÷3
,
=
;
(4)∵x=
=
+1,
∴x2-x+1,
=(
+1)2-(
+1)+1,
=4+2
-
-1+1,
=4+
.
| 8 |
| 2 |
| 2 |
=2
| 2 |
| 2 |
=-2;
(2)
| 2 | ||
|
| 27 |
| 3 |
|
=
| 3 |
| 3 |
| 1 |
| 4 |
| 3 |
=3
| 3 |
| 1 |
| 4 |
(3)(6
|
|
| x |
=(3
| x |
| x |
| x |
=
| 1 |
| 3 |
(4)∵x=
| 2 | ||
|
| 3 |
∴x2-x+1,
=(
| 3 |
| 3 |
=4+2
| 3 |
| 3 |
=4+
| 3 |
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