题目内容

计算或化简:
(1)
8
-
2
(
2
+2)

(2)
2
3
-1
+
27
-(
3
-1)0+(-2)-2-3
1
3

(3)(6
x
4
-2x
1
x
)÷3
x

(4)已知:x=
2
3
-1
,求x2-x+1的值.
(1)
8
-
2
(
2
+2)

=2
2
-2-2
2

=-2;

(2)
2
3
-1
+
27
-(
3
-1)0+(-2)-2-3
1
3

=
3
+1+3
3
-1+
1
4
-
3

=3
3
+
1
4


(3)(6
x
4
-2x
1
x
)÷3
x

=(3
x
-2
x
÷3
x

=
1
3


(4)∵x=
2
3
-1
=
3
+1

∴x2-x+1,
=(
3
+1
2-(
3
+1
)+1,
=4+2
3
-
3
-1+1,
=4+
3
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网