题目内容
①解方程:2-
=1;
②利用①的结果,先化简代数式(1+
)÷
,再求值.
| 1 |
| x-1 |
②利用①的结果,先化简代数式(1+
| 1 |
| x-1 |
| x |
| x2-1 |
①方程两边同乘x-1,得
2(x-1)-1=x-1,
解得x=2.经检验x=2是原方程的解.
∵(1+
)÷
=
×
=x+1.
②当x=2时,原式=2+1=3.
2(x-1)-1=x-1,
解得x=2.经检验x=2是原方程的解.
∵(1+
| 1 |
| x-1 |
| x |
| x-1 |
=
| x |
| x-1 |
| (x-1)(x+1) |
| x |
=x+1.
②当x=2时,原式=2+1=3.
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