题目内容
(6分)某初级中学准备随机选出七、八、九三个年级各1名学生担任领操员.现已知这三个年级分别选送一男、一女共6名学生为备选人.
1.(1)请你利用树状图或表格列出所有可能的选法;
2.(2)求选出“两男一女”三名领操员的概率.
【答案】
1.解法一:(1)用表格列出所有可能结果:
|
七年级 |
八年级 |
九年级 |
结果 |
|
男 |
男 |
男 |
(男,男,男) |
|
男 |
男 |
女 |
(男,男,女) |
|
男 |
女 |
男 |
(男,女,男) |
|
男 |
女 |
女 |
(男,女,女) |
|
女 |
女 |
女 |
(女,女,女) |
|
女 |
女 |
男 |
(女,女,男) |
|
女 |
男 |
女 |
(女,男,女) |
|
女 |
男 |
男 |
(女,男,男) |
····································································································································· 3分
解法二:(1)用树状图列出所有可能结果:
![]()
····································································································································· 3分
2.(2)从上表可知:共有8种结果,且每种结果都是等可能的,其中“两男一女”的结果有3种. 5分
所以,P(两男一女)=.··························································································· 6分
【解析】略
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