题目内容
先化简再求值:(| x+1 |
| x2-4 |
| 2 |
| x+2 |
| x-5 |
| x+2 |
| 2 |
分析:先把括号里式子通分,再把除法转化为乘法,约分化为最简,最后代值计算.
解答:解:原式=(
-
)×
=
×
=-
,
当x=
+2时,原式=-
=-
.
| x+1 |
| (x+2)(x-2) |
| 2(x-2) |
| (x+2)(x-2) |
| x+2 |
| x-5 |
=
| 5-x |
| (x+2)(x-2) |
| x+2 |
| x-5 |
| 1 |
| x-2 |
当x=
| 2 |
| 1 | ||
|
| ||
| 2 |
点评:本题主要考查分式的化简求值这一知识点,把分式化到最简是解答的关键.
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