题目内容
先化简,再求值:
÷
+
,其中x=2.
| x-1 |
| x+2 |
| x2-2x+1 |
| x2-4 |
| 2 |
| x-1 |
分析:先根据分式混合运算的法则把原式进行化简,再把x=1代入进行计算即可.
解答:解:原式=
•
+
=
•
+
=
+
=
=
.
当x=2时,原式=
=2.
| x-1 |
| x+2 |
| x2-4 |
| x2-2x+1 |
| 2 |
| x-1 |
=
| x-1 |
| x+2 |
| (x+2)(x-2) |
| (x-1)2 |
| 2 |
| x-1 |
=
| x-2 |
| x-1 |
| 2 |
| x-1 |
=
| x-2+2 |
| x-1 |
=
| x |
| x-1 |
当x=2时,原式=
| 2 |
| 2-1 |
点评:本题考查的是分式的化简求值,在解答此类题目时要注意通分及约分的灵活应用.
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