题目内容
计算:
(1)(π-2009)0+
+|
-2|;
(2)
-4.
(1)(π-2009)0+
| 12 |
| 3 |
(2)
| ||||
|
(1)原式=1+2
+2-
=3+
;
(2)原式=
-4
=
-4
=
.
| 3 |
| 3 |
=3+
| 3 |
(2)原式=
5
| ||||
2
|
=
| 9 |
| 2 |
=
| 1 |
| 2 |
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题目内容
| 12 |
| 3 |
| ||||
|
| 3 |
| 3 |
| 3 |
5
| ||||
2
|
| 9 |
| 2 |
| 1 |
| 2 |