题目内容
(2013•浦东新区二模)先化简,再求值:
-
-
,其中x=
-2.
| x+2 |
| x-2 |
| 16 |
| x2-4 |
| 1 |
| x+2 |
| 3 |
分析:原式三项通分并利用同分母分式的加减法则计算得到最简结果,将x的值代入计算即可求出值.
解答:解:原式=
-
-
=
=
=
=
,
当x=
-2时,原式=
=1+
.
| x+2 |
| x-2 |
| 16 |
| (x+2)(x-2) |
| 1 |
| x+2 |
=
| (x+2)2-16-(x-2) |
| (x+2)(x-2) |
=
| x2+3x-10 |
| (x+2)(x-2) |
=
| (x-2)(x+5) |
| (x+2)(x-2) |
=
| x+5 |
| x+2 |
当x=
| 3 |
| ||
|
| 3 |
点评:此题考查了分式的化简求值,分式的加减运算关键是通分,通分的关键是找最简公分母;分式的乘除运算关键是约分,约分的关键是找公因式.
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