题目内容
计算题:
(1)-
+
-
+
;
(2)(-1
)-(-3.2)+|-1.8|;
(3)-13÷
×(-3);
(4)-12×(1
-
+
);
(5)(-81)÷
×
÷(-16);
(6)[2
-(
+
-
)×24]÷5×(-1)2001;
(7)-22-(-1)2001×(
-
)÷
+(-3)2;
(8)3(x2-2xy)-[3x2-2y+2(xy+y)],其中x=-
,y=-3.
(1)-
| 7 |
| 12 |
| 6 |
| 11 |
| 5 |
| 12 |
| 5 |
| 11 |
(2)(-1
| 3 |
| 5 |
(3)-13÷
| 1 |
| 9 |
(4)-12×(1
| 1 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
(5)(-81)÷
| 9 |
| 4 |
| 4 |
| 9 |
(6)[2
| 1 |
| 2 |
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
(7)-22-(-1)2001×(
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
(8)3(x2-2xy)-[3x2-2y+2(xy+y)],其中x=-
| 1 |
| 2 |
考点:整式的加减—化简求值,有理数的混合运算
专题:
分析:(1)直接利用有理数加减运算法则化简求出即可;
(2)直接利用有理数加减运算法则化简求出即可;
(3)直接利用有理数乘除运算法则化简求出即可;
(4)直接利用有理数乘法运算法则化简求出即可;
(5)直接利用有理数乘除运算法则化简求出即可;
(6)直接利用有理数乘除运算法则化简求出即可;
(7)首先化简各数,进而求出即可;
(8)首先去括号,进而合并同类项,进而求出即可.
(2)直接利用有理数加减运算法则化简求出即可;
(3)直接利用有理数乘除运算法则化简求出即可;
(4)直接利用有理数乘法运算法则化简求出即可;
(5)直接利用有理数乘除运算法则化简求出即可;
(6)直接利用有理数乘除运算法则化简求出即可;
(7)首先化简各数,进而求出即可;
(8)首先去括号,进而合并同类项,进而求出即可.
解答:解:(1)-
+
-
+
=-1+1
=0;
(2)(-1
)-(-3.2)+|-1.8|
=-1.6+3.2+1.8
=3.4;
(3)-13÷
×(-3)
=-1×9×(-3)
=27;
(4)-12×(1
-
+
)
=-12×
+(-12)×(-
)+(-12)×
=-16+9-10
=-17;
(5)(-81)÷
×
÷(-16)
=(-81)×
×
×(-
)
=1;
(6)[2
-(
+
-
)×24]÷5×(-1)2001
=(2.5-9-4+18)×
×(-1)
=-1.5;
(7)-22-(-1)2001×(
-
)÷
+(-3)2
=-4+1×(2-3)+9
=4;
(8)3(x2-2xy)-[3x2-2y+2(xy+y)],
=3x2-6xy-3x2+2y-2(xy+y)
=-8xy
将x=-
,y=-3代入得:
原式=-8xy=-8×(-
)×(-3)=-12.
| 7 |
| 12 |
| 6 |
| 11 |
| 5 |
| 12 |
| 5 |
| 11 |
=-1+1
=0;
(2)(-1
| 3 |
| 5 |
=-1.6+3.2+1.8
=3.4;
(3)-13÷
| 1 |
| 9 |
=-1×9×(-3)
=27;
(4)-12×(1
| 1 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
=-12×
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
=-16+9-10
=-17;
(5)(-81)÷
| 9 |
| 4 |
| 4 |
| 9 |
=(-81)×
| 4 |
| 9 |
| 4 |
| 9 |
| 1 |
| 16 |
=1;
(6)[2
| 1 |
| 2 |
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
=(2.5-9-4+18)×
| 1 |
| 5 |
=-1.5;
(7)-22-(-1)2001×(
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
=-4+1×(2-3)+9
=4;
(8)3(x2-2xy)-[3x2-2y+2(xy+y)],
=3x2-6xy-3x2+2y-2(xy+y)
=-8xy
将x=-
| 1 |
| 2 |
原式=-8xy=-8×(-
| 1 |
| 2 |
点评:此题主要考查了整式的化简求值以及实数运算,正确化简各整式是解题关键.
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