题目内容
先化简,再求值:
(1)(x+2y)(2x+y)-(x+2y)(2y-x),其中x=
,y=
.
(2)若x-y=1,xy=2,求x3y-2x2y2+xy3.
(1)(x+2y)(2x+y)-(x+2y)(2y-x),其中x=
| 1 |
| 3 |
| 1 |
| 2 |
(2)若x-y=1,xy=2,求x3y-2x2y2+xy3.
(1)原式=(x+2y)(2x+y-2y+x)
=(x+2y)(3x-y)
=3x2+5xy-2y2,
当x=
,y=
时,原式=3×
+5×
×
-2×
=
;
(2)原式=xy(x-y)2,
当x-y=1,xy=2时,原式=2×1=2.
=(x+2y)(3x-y)
=3x2+5xy-2y2,
当x=
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 9 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
(2)原式=xy(x-y)2,
当x-y=1,xy=2时,原式=2×1=2.
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