题目内容
计算:
-
=
| x-3 |
| x2-1 |
| 2 |
| 1+x |
-
| 1 |
| x-1 |
-
.| 1 |
| x-1 |
分析:首先通分,然后利用同分母的分式相加减的运算法则求解即可求得答案.
解答:解:
-
=
=
=
=-
.
故答案为:-
.
| x-3 |
| x2-1 |
| 2 |
| 1+x |
| x-3-2(x-1) |
| (x-1)(x+1) |
| x-3-2x+2 |
| (x+1)(x-1) |
| -x-1 |
| (x+1)(x-1) |
| 1 |
| x-1 |
故答案为:-
| 1 |
| x-1 |
点评:此题考查了分式的加减运算法则.此题比较简单,注意运算结果要化为最简.
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