题目内容
计算与解方程:
(1)x(2x-1)=3(2x-1);
(2)
+6
-2x
.
(1)x(2x-1)=3(2x-1);
(2)
| 2 |
| 3 |
| 9x |
|
|
(1)∵x(2x-1)-3(2x-1)=0,
∴(2x-1)(x-3)=0,
∴2x-1=0或x-3=0,
∴x1=
,x2=3;
(2)原式=
×3
+6×
-2x•
=2
+3
-2
=3
.
∴(2x-1)(x-3)=0,
∴2x-1=0或x-3=0,
∴x1=
| 1 |
| 2 |
(2)原式=
| 2 |
| 3 |
| x |
| 1 |
| 2 |
| x |
| 1 |
| x |
| x |
=2
| x |
| x |
| x |
=3
| x |
练习册系列答案
相关题目