题目内容
计算(7| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
分析:根据积的乘方运算以及平方差公式得出原式=[(7
)2-(5
)2]
,进而利用幂的乘方运算得出答案.
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
解答:解:原式=[(7
-5
)(7
+5
)]
,
=[(7
)2-(5
)2]
,
=2
,
=
.
故答案为:
.
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
=[(7
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
=2
| 1 |
| 3 |
=
| 3 | 2 |
故答案为:
| 3 | 2 |
点评:此题主要考查了实数运算,是各地中考题中常见的计算题型.解决此类题目的关键是熟练掌握整数指数幂、积的乘方、以及平方差公式等考点的运算.
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