题目内容
计算.
(1)
-
(2)
+
.
(1)
| x |
| x-3 |
| x |
| x+3 |
(2)
| 1 |
| m+2 |
| 4 |
| m2-4 |
分析:首先把异分母转化成同分母,然后进行加减运算即可.
解答:解:(1)
-
=
-
=
;
(2)
+
=
+
=
.
| x |
| x-3 |
| x |
| x+3 |
=
| x(x+3) |
| (x-3)(x+3) |
| x(x-3) |
| (x-3)(x+3) |
=
| 6x |
| x2-9 |
(2)
| 1 |
| m+2 |
| 4 |
| m2-4 |
=
| m-2 |
| (m+2)(m-2) |
| 4 |
| (m+2)(m-2) |
=
| 1 |
| m-2 |
点评:此题考查了分式的加减法,在分式的加减运算中,如果是同分母分式,那么分母不变,把分子直接相加减即可;如果是异分母分式,则必须先通分,把异分母分式化为同分母分式,然后再相加减.
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