题目内容

①5xy2+2x2y-3xy2-x2y
②2x-(x+3y)-(-x-y)+(x-y)
③(5a2+2b2)-3(a2-4b2
④a2-2[a2-(2a2-b)].
分析:①直接合并同类项即可;
②、③、④先去括号,再合并同类项.
解答:解:①原式=(5-3)xy2+(2-1)x2y
=2xy2+x2y;

②原式=2x-x-3y+x+y+x-y
=(2-1+1+1)x-(3-1+1)y
=3x-3y;

③原式=5a2+2b2-3a2+12b2
=(5-3)a2+(2+12)b2
=2a2+14b2

④原式=a2-2[a2-2a2+b]
=a2+2a2-2b
=3a2-2b.
点评:本题考查的是整式的加减,熟知整式的加减实质上是合并同类项是解答此题的关键.
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