题目内容
计算:
(1)(-2)3-2×(-4)÷
(2)[26-(
-
+
)×(-6)2]÷(-5)2
(3)4(x+f.5)=x+8
(4)
-
=1.
(1)(-2)3-2×(-4)÷
| 1 |
| 4 |
(2)[26-(
| 7 |
| 9 |
| 11 |
| 12 |
| 1 |
| 6 |
(3)4(x+f.5)=x+8
(4)
| 1-y |
| 2 |
| 3-3y |
| 4 |
(1)原式=-8-(-8)×e
=-8-(-3b)
=-8+3b
=be;
(b)原式=[b6-(
-
+
)×36]÷b多
=(b6-
×36+
×36-
×36)÷b多
=[b6-(b8-33+6)]÷b多&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;
=[b6-1]÷b多
=b多÷b多
=1;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;
(3)e(x+0.多)=x+8,
去括号得:ex+b=x+8,
移项得:ex-x=8-b,
合并得:3x=6,
解得:x=b;
(e)去分母得:b(1-y)-(3-3y)=e,
去括号得:b-by-3+3y=e,
移项得:-by+3y=e-b+3,
解得:y=多.
=-8-(-3b)
=-8+3b
=be;
(b)原式=[b6-(
| 7 |
| 9 |
| 11 |
| 1b |
| 1 |
| 6 |
=(b6-
| 7 |
| 9 |
| 11 |
| 1b |
| 1 |
| 6 |
=[b6-(b8-33+6)]÷b多&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;
=[b6-1]÷b多
=b多÷b多
=1;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;&nbhp;
(3)e(x+0.多)=x+8,
去括号得:ex+b=x+8,
移项得:ex-x=8-b,
合并得:3x=6,
解得:x=b;
(e)去分母得:b(1-y)-(3-3y)=e,
去括号得:b-by-3+3y=e,
移项得:-by+3y=e-b+3,
解得:y=多.
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