题目内容
计算:
(1)-24-(10-15)
(2)(-7)+(+6)-(+9)-(-4)
(3)1-(-
)+(-
)-
(4)(-4
)-(-5
)+(-4
)-3
.
(1)-24-(10-15)
(2)(-7)+(+6)-(+9)-(-4)
(3)1-(-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 6 |
(4)(-4
| 7 |
| 8 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
分析:(1)首先计算括号内的数,然后进行加减即可;
(2)首先利用符号法则对式子进行化简,然后把正数与负数分别相加,然后把结果相加即可;
(3)首先利用符号法则对式子进行化简,然后通分,进行加减;
(4)首先利用符号法则对式子进行化简,首先计算同分母的分数,然后进行通分相加即可求解.
(2)首先利用符号法则对式子进行化简,然后把正数与负数分别相加,然后把结果相加即可;
(3)首先利用符号法则对式子进行化简,然后通分,进行加减;
(4)首先利用符号法则对式子进行化简,首先计算同分母的分数,然后进行通分相加即可求解.
解答:解:(1)原式=-24-(-5)
=-24+5
=-19;
(2)原式=-7+6-9+4
=-7-9+6+4
=-16+10
=-6;
(3)原式=1+
-
-
=
+
-
-
=1;
(4)原式=-4
+5
-4
-3
=-4
-3
+5
-4
=-8+
-
=-8+1
=-7.
=-24+5
=-19;
(2)原式=-7+6-9+4
=-7-9+6+4
=-16+10
=-6;
(3)原式=1+
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 6 |
=
| 6 |
| 6 |
| 3 |
| 6 |
| 2 |
| 6 |
| 1 |
| 6 |
=1;
(4)原式=-4
| 7 |
| 8 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
=-4
| 7 |
| 8 |
| 1 |
| 8 |
| 1 |
| 2 |
| 1 |
| 4 |
=-8+
| 22 |
| 4 |
| 17 |
| 4 |
=-8+1
=-7.
点评:本题主要考查有理数的异分母分数加减混合运算,通分是解题的关键.
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