题目内容
计算(1-| 3 |
| x+2 |
| x |
| x-1 |
分析:首先把括号里的式子进行通分,然后进行约分化简.
解答:解:原式=
•
=
=
.
故答案为
.
| x+2-3 |
| x+2 |
| x |
| x-1 |
=
| x(x-1) |
| (x+2)(x-1) |
=
| x |
| x+2 |
故答案为
| x |
| x+2 |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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题目内容
计算(1-| 3 |
| x+2 |
| x |
| x-1 |
| x+2-3 |
| x+2 |
| x |
| x-1 |
| x(x-1) |
| (x+2)(x-1) |
| x |
| x+2 |
| x |
| x+2 |