题目内容
计算与化简
(1)
-
-
;
(2)
-
;
(3)
;
(4)
+
-
.
(1)
| 3 |
| x |
| 6 |
| 1-x |
| x+5 |
| x2-x |
(2)
| a2 |
| a+1 |
| 1 |
| a+1 |
(3)
1-
|
(4)
| 0.04 |
| 3 | -8 |
|
考点:分式的加减法,实数的运算
专题:
分析:(1)首先通分,把分母化为x(x-1),然后分母不变,分子相加减即可;
(2)分母不变,只把分子相减,然后再约分;
(3)首先计算出被开方数,然后再开方即可;
(4)先开方,然后计算加减即可.
(2)分母不变,只把分子相减,然后再约分;
(3)首先计算出被开方数,然后再开方即可;
(4)先开方,然后计算加减即可.
解答:解:(1)原式=
+
-
=
=
;
(2)原式=
=a-1;
(3)原式=
=
;
(4)原式=0.2-2-
=-2.3.
| 3(x-1) |
| x(x-1) |
| 6x |
| x(x-1) |
| x+5 |
| x(x-1) |
| 8x-8 |
| x(x-1) |
| 8 |
| x |
(2)原式=
| (a+1)(a-1) |
| a+1 |
(3)原式=
|
| 3 |
| 5 |
(4)原式=0.2-2-
| 1 |
| 2 |
点评:此题主要考查了分式的运算,以及实数的运算,关键是掌握异分母分式加减法法则:把分母不相同的几个分式化成分母相同的分式,叫做通分,经过通分,异分母分式的加减就转化为同分母分式的加减,然后计算.
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