题目内容
(10分) 如图,Rt△ABC中,∠C = 90°,把Rt△ABC绕着B点逆时针旋转,得到Rt△DBE,点E在AB上.![]()
(1)若∠BDA = 70°,求∠BAC的度数.
(2)若BC = 8,AC = 6,求△ABD中AD边上的高.
(1)∠BAC =![]()
(2)![]()
解析解:(1) 由旋转得△ACB≌△DEB
∴BD = BA
∴∠BAD =∠BDA =![]()
∴∠ABD =![]()
∴∠ABC =∠ABD =![]()
∵∠C =![]()
∴∠BAC =
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(2) ∵BC = 8,AC = 6,∠C =![]()
∴![]()
∵∠DEB =∠C =
且BE = BC = 8,DE ="AC" = 6
∴AE =" AB" – BE = 2
在Rt△DEA中,![]()
设AD边上的高为h
∴![]()
∴
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