题目内容
计算:
(1)-9÷3+(
-
)×12+32;
(2)-1-[2-(1-
×0.5)]×[32-(-2)2];
(3)-2×(-
)2+|-(-2)|3-(-
).
(1)-9÷3+(
| 1 |
| 2 |
| 2 |
| 3 |
(2)-1-[2-(1-
| 1 |
| 3 |
(3)-2×(-
| 1 |
| 2 |
| 1 |
| 2 |
(1)原式=-3+(-
)×12+9=-3-2+9=4;
(2)原式=-1-[2-(1-
)]×(9-4)
=-1-(2-
)×5
=-1-
×5
=-1-
=-
;
(3)原式=-2×
+8+
=-
+8+
=8.
| 1 |
| 6 |
(2)原式=-1-[2-(1-
| 1 |
| 6 |
=-1-(2-
| 5 |
| 6 |
=-1-
| 7 |
| 6 |
=-1-
| 35 |
| 6 |
=-
| 41 |
| 6 |
(3)原式=-2×
| 1 |
| 4 |
| 1 |
| 2 |
=-
| 1 |
| 2 |
| 1 |
| 2 |
=8.
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