题目内容
计算:
-
.
| 2x |
| x2-1 |
| 2 |
| x2-1 |
分析:原式利用同分母分式的减法法则计算,约分即可得到结果.
解答:解:原式=
=
=
.
| 2x-2 |
| x2-1 |
| 2(x-1) |
| (x+1)(x-1) |
| 2 |
| x+1 |
点评:此题考查了分式的加减法,分式的加减运算关键是通分,通分的关键是找最简公分母.
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题目内容
| 2x |
| x2-1 |
| 2 |
| x2-1 |
| 2x-2 |
| x2-1 |
| 2(x-1) |
| (x+1)(x-1) |
| 2 |
| x+1 |