题目内容
计算.
(1)-0.52+(-
)2-|-22-4|-(-1
)3×(
)3÷(-
)4
(2){[3
÷(-
)+0.4×(-
)2]÷(-
)-20}×(-1)2005
(1)-0.52+(-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
(2){[3
| 3 |
| 4 |
| 1 |
| 4 |
| 5 |
| 2 |
| 5 |
| 3 |
(1)原式=-0.25+
-|-4|-(-
)×
÷
=-.025+
-4+
÷
=-0.25+
-4+2
=-0.25+0.25-4+2
=-2.
(2)原式={[
÷(-
)+0.4×
]÷(-
)-20}×(-1)
={[-15+
]÷(-
)-20}×(-1)
=[-
÷(-
)-20]×(-1)
=12
.
| 1 |
| 4 |
| 27 |
| 8 |
| 1 |
| 27 |
| 1 |
| 16 |
=-.025+
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
=-0.25+
| 1 |
| 4 |
=-0.25+0.25-4+2
=-2.
(2)原式={[
| 15 |
| 4 |
| 1 |
| 4 |
| 25 |
| 4 |
| 5 |
| 3 |
={[-15+
| 5 |
| 2 |
| 5 |
| 3 |
=[-
| 25 |
| 2 |
| 5 |
| 3 |
=12
| 1 |
| 2 |
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