题目内容
已知x(x-1)-(x2-y)=-2,求
-xy的值.
| x2+y2 |
| 2 |
∵x(x-1)-(x2-y)=-2,
∴x2-x-x2+y=-2,
∴x-y=2,
∴
-xy=
=
=2.
∴x2-x-x2+y=-2,
∴x-y=2,
∴
| x2+y2 |
| 2 |
| x2+y2-2xy |
| 2 |
| (x-y)2 |
| 2 |
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题目内容
| x2+y2 |
| 2 |
| x2+y2 |
| 2 |
| x2+y2-2xy |
| 2 |
| (x-y)2 |
| 2 |