题目内容
先化简,再求值:(| x |
| x+2 |
| x |
| x-2 |
| 4x |
| 2-x |
| 3 |
分析:括号里通分,将除法化为乘法,约分化简,再代值计算.
解答:解:原式=
•(-
),
=
•(-
),
=
,
当x=2-
时,原式=
=4+
.
| x(x-2)-x(x+2) |
| (x+2)(x-2) |
| x-2 |
| 4x |
=
| -4x |
| (x+2)(x-2) |
| x-2 |
| 4x |
=
| 1 |
| x+2 |
当x=2-
| 3 |
| 1 | ||
2-
|
| 3 |
点评:本题考查了分式的化简求值.解答此题的关键是把分式化到最简,然后代值计算.
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