题目内容
先化简再求值
÷(a+1)+
,其中a=
+1.
| 2a+2 |
| a-1 |
| a2-1 |
| a2-2a+1 |
| 3 |
原式=
•
+
,
=
+
,
=
,
当a=
+1时,原式=
.
| 2(a+1) |
| a-1 |
| 1 |
| a+1 |
| (a+1)(a-1) |
| (a-1)2 |
=
| 2 |
| a-1 |
| (a+1)(a-1) |
| (a-1)2 |
=
| a+3 |
| a-1 |
当a=
| 3 |
3+4
| ||
| 3 |
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