题目内容
已知1-x与y+1互为倒数,则
-
=______.
| 1 |
| y |
| 1 |
| x |
∵1-x与y+1互为倒数,
∴(1-x)(y+1)=1,整理得xy=y-x,
∴
-
=
=
=-1.
故答案为-1.
∴(1-x)(y+1)=1,整理得xy=y-x,
∴
| 1 |
| y |
| 1 |
| x |
| x-y |
| xy |
| x-y |
| y-x |
故答案为-1.
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题目内容
| 1 |
| y |
| 1 |
| x |
| 1 |
| y |
| 1 |
| x |
| x-y |
| xy |
| x-y |
| y-x |