题目内容
①解方程:2-| 1 |
| x-1 |
②利用①的结果,先化简代数式(1+
| 1 |
| x-1 |
| x |
| x2-1 |
分析:①观察可得最简公分母为(x-1),去分母后将分式方程求解.同时对②进行化简,即:(1+
)÷
=
÷
=x+1,再将①求得数值代入②求值即可.
| 1 |
| x-1 |
| x |
| x2-1 |
| x-1+1 |
| x-1 |
| x |
| (x+1)(x-1) |
解答:解:①方程两边同乘x-1,得
2(x-1)-1=x-1,
解得x=2.经检验x=2是原方程的解.
∵(1+
)÷
=
×
=x+1.
②当x=2时,原式=2+1=3.
2(x-1)-1=x-1,
解得x=2.经检验x=2是原方程的解.
∵(1+
| 1 |
| x-1 |
| x |
| x-1 |
=
| x |
| x-1 |
| (x-1)(x+1) |
| x |
=x+1.
②当x=2时,原式=2+1=3.
点评:解分式方程要注意最简公分母的确定,同时求解后要进行检验;②中要化简后再代入求值.
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