题目内容


某商品的进价为每件40元,售价为每件50元,每个月可卖出210件.如果每件商品的售价每上涨1元,则每个月少卖10件.当每件商品的售价定为多少元时,每个月的利润恰为2200元?


解法一:设每件商品的售价上涨x元,

(210-10x)(50+x-40)=2200··································································· 4分

解得x1 =1,x2=10,··············································································· 6分

∴当x=1时,50+x=51,当x=10时,50+x=60;······························· 7分

解法二:设每件商品的售价为x元,

[210-10(x-50)] (x-40)=2200································································ 4分

解得x1 =51,x2=60,············································································· 7分

答:当每件商品的售价定为51或60元时,每个月的利润恰为2200元.··· 8分


练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网