题目内容
某商品的进价为每件40元,售价为每件50元,每个月可卖出210件.如果每件商品的售价每上涨1元,则每个月少卖10件.当每件商品的售价定为多少元时,每个月的利润恰为2200元?
解法一:设每件商品的售价上涨x元,
(210-10x)(50+x-40)=2200··································································· 4分
解得x1 =1,x2=10,··············································································· 6分
∴当x=1时,50+x=51,当x=10时,50+x=60;······························· 7分
解法二:设每件商品的售价为x元,
[210-10(x-50)] (x-40)=2200································································ 4分
解得x1 =51,x2=60,············································································· 7分
答:当每件商品的售价定为51或60元时,每个月的利润恰为2200元.··· 8分
某鞋店一天中卖出运动鞋11双,其中各种尺码的鞋的销售量如下表:
| 尺码(cm) | 23.5 | 24 | 24.5 | 25 | 25.5 |
| 销售量(双) | 1 | 2 | 2 | 5 | 1 |
则这11双鞋的尺码组成的一组数据中,众数和中位数分别是( )
A.25,25 B.24.5,25 C.25,24.5 D.24.5,24.5
据有关资料显示,2014年通过国家科技支撑计
划,遵义市获得国家级科技专项重点项目资金5533万元,将5533万用科学记数法可表示为( )
|
| A. | 5.533×108 | B. | 5.533×107 | C. | 5.533×106 | D. | 55.33×106 |