题目内容
先化简,再求值| x-1 |
| x |
| 1 |
| x |
分析:先把分式化简,再将未知数的值代入求解.
解答:解:原式=
÷
=
×
=
;
当x=2时,原式=
=
.
| x-1 |
| x |
| x2-1 |
| x |
| x-1 |
| x |
| x |
| (x+1)(x-1) |
| 1 |
| x+1 |
当x=2时,原式=
| 1 |
| 2+1 |
| 1 |
| 3 |
点评:本题考查了分式的混合运算以及多项式的因式分解.
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题目内容
先化简,再求值| x-1 |
| x |
| 1 |
| x |
| x-1 |
| x |
| x2-1 |
| x |
| x-1 |
| x |
| x |
| (x+1)(x-1) |
| 1 |
| x+1 |
| 1 |
| 2+1 |
| 1 |
| 3 |