题目内容
先化简再求值:(| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
分析:先通分,然后进行四则运算,最后将x=1代入.
解答:解:原式=[
-
]•
=
•
=
.
当x=1时,原式=
=
=1.
| (x+2)(x-2) |
| x(x-2)2 |
| x(x-1) |
| x(x-2)2 |
| x |
| x-4 |
=
| x2-4-x2+x |
| x(x-2)2 |
| x |
| x-4 |
=
| 1 |
| (x-2)2 |
当x=1时,原式=
| 1 |
| (x-2)2 |
| 1 |
| (1-2)2 |
点评:本题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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