题目内容
计算:
(1)(-2a2b)2•(-ab)÷(-
b2)
(2)(-2a2)•(3ab2-5ab3)
(3)(x+2)2-(x-2)2
(4)(3x4-2x3)÷(-x)-(x-x2)•3x
(1)(-2a2b)2•(-ab)÷(-
| 1 |
| 2 |
(2)(-2a2)•(3ab2-5ab3)
(3)(x+2)2-(x-2)2
(4)(3x4-2x3)÷(-x)-(x-x2)•3x
(1)(-2a2b)2•(-ab)÷(-
b2),
=4a4b2(-ab)÷(-
b2),
=-4a5b3÷(-
b2),
=8a5b;
(2)(-2a2)•(3ab2-5ab3),
=(-2a2)3ab2-(-2a2)5ab3,
=-6a3b2+10a3b3;
(3)(x+2)2-(x-2)2,
=(x2+4x+4)-(x2-4x+4),
=x2+4x+4-x2+4x-4,
=8x;
或利用平方差公式:
(x+2)2-(x-2)2,
=(x+2+x-2)(x+2-x+2),
=8x.
(4)(3x4-2x3)÷(-x)-(x-x2)•3x,
=-3x3+2x2-3x2+3x3,
=-x2.
| 1 |
| 2 |
=4a4b2(-ab)÷(-
| 1 |
| 2 |
=-4a5b3÷(-
| 1 |
| 2 |
=8a5b;
(2)(-2a2)•(3ab2-5ab3),
=(-2a2)3ab2-(-2a2)5ab3,
=-6a3b2+10a3b3;
(3)(x+2)2-(x-2)2,
=(x2+4x+4)-(x2-4x+4),
=x2+4x+4-x2+4x-4,
=8x;
或利用平方差公式:
(x+2)2-(x-2)2,
=(x+2+x-2)(x+2-x+2),
=8x.
(4)(3x4-2x3)÷(-x)-(x-x2)•3x,
=-3x3+2x2-3x2+3x3,
=-x2.
练习册系列答案
相关题目