题目内容
计算
(1)12+(-8)+11+(-2)+(-12);
(2)
÷(
+
-
);
(3)(-1)3×(-5)÷[-32+(-2)2].
(1)12+(-8)+11+(-2)+(-12);
(2)
| 1 |
| 18 |
| 2 |
| 3 |
| 1 |
| 6 |
| 1 |
| 2 |
(3)(-1)3×(-5)÷[-32+(-2)2].
分析:(1)先去括号,再从左到右依次计算即可;
(2)先算括号里面的,再算除法即可;
(3)先算括号里面的,再算乘方,最后算乘除.
(2)先算括号里面的,再算除法即可;
(3)先算括号里面的,再算乘方,最后算乘除.
解答:解:(1)原式=12-8+11-2-12
=4+11-2-12
=15-2-12
=13-12
=1;
(2)原式=
÷
=
×3
=
;
(3)原式=(-1)3×(-5)÷[-9+4]
=(-1)×(-5)×(-
)
=5×(-
)
=-1.
=4+11-2-12
=15-2-12
=13-12
=1;
(2)原式=
| 1 |
| 18 |
| 1 |
| 3 |
=
| 1 |
| 18 |
=
| 1 |
| 6 |
(3)原式=(-1)3×(-5)÷[-9+4]
=(-1)×(-5)×(-
| 1 |
| 5 |
=5×(-
| 1 |
| 5 |
=-1.
点评:本题考查的是有理数的混合运算,熟知有理数混合运算的法则是解答此题的关键.
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