题目内容
如果一个数列|an|满足a1=2,an+1=an+2n(n为自然数),那么a100是
- A.9900
- B.9902
- C.9904
- D.10100
- E.10102
B
a100=a99+2×99=a98+2×98+2×99=…=a1+2×1+2×2+…+2×99=2+2×(1+2+…+99)=2+2×4950=9902.所以选B
a100=a99+2×99=a98+2×98+2×99=…=a1+2×1+2×2+…+2×99=2+2×(1+2+…+99)=2+2×4950=9902.所以选B
练习册系列答案
相关题目
如果一个数列|an|满足a1=2,an+1=an+2n(n为自然数),那么a100是
[ ]
|
A.9900 |
B.9902 |
|
C.9904 |
D.10100 |
|
E.10102 |