题目内容
已知:
=
=
则(x+y):z的值为
| x+y |
| z |
| y+z |
| x |
| z+x |
| y |
2或-1
2或-1
.分析:此题应考虑两种情况:当x+y+z≠0时,根据等比性质求解;当x+y+z=0时,从中导出x+y=-z,代入即可求解
解答:解:当x+y+z≠0时,则有(x+y):z=
=2;
当x+y+z=0时,则有x+y=-z,即(x+y):z=-1.
故答案为2或-1.
| 2x+2y+2z |
| x+y+z |
当x+y+z=0时,则有x+y=-z,即(x+y):z=-1.
故答案为2或-1.
点评:此题主要考查等比性质的运用:若
=
=…=
=k,则
=k(b+d+…+n≠0).
| a |
| b |
| c |
| d |
| m |
| n |
| a+c+…+m |
| b+d+…+n |
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