题目内容

(本小题满分9分)已知⊙与⊙相交于两点,点在⊙上,为⊙上一点(不与重合),直线与⊙交于另一点

(1)如图(8),若是⊙的直径,求证:

(2)如图(9),若是⊙外一点,求证:

(3)如图(10),若是⊙内一点,判断(2)中的结论是否成立。

 

【答案】

证明:(1)如图(一),连接

为⊙的直径      ∴

为⊙的直径      ∴

的中点

∴△是以为底边的等腰三角形

····················································································· (3分)

(2)如图(二),连接,并延长交⊙与点,连

∵四边形内接于⊙    ∴

又∵                ∴

为⊙的直径           ∴

···················································································· (3分)

(3)如图(三),连接,并延长交⊙与点,连

         又

 

            又

···················································································· (3分)

【解析】略

 

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