题目内容
如图,平行四边形ABCD中,E是AB上一点,DE与AC相交于F,若
=3,则
=______.
| AE |
| EB |
| AF |
| FC |
若
=3,则
=
=
,
又AB∥CD,
△AEF∽△CDF,
因而
=
=
.
| AE |
| EB |
| AE |
| AB |
| AE |
| CD |
| 3 |
| 4 |
又AB∥CD,
△AEF∽△CDF,
因而
| AF |
| FC |
| AE |
| CD |
| 3 |
| 4 |
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