题目内容
计算
(1)(
a2bx)-(-2abx)2
(2)-2(1-
)-4x(2-
)
(3)(-2)2012×0.125671.
(1)(
| 1 |
| 2 |
(2)-2(1-
| 3x |
| 2 |
| x-1 |
| 4 |
(3)(-2)2012×0.125671.
(1)(
a2bx)•(-2abx)2
=(
a2bx)• 4a2b2x2
=2a4b3x3 ;
(2)-2(1-
)-4x(2-
)
=-2+3x-8x+x(x-1)
=-2+3x-8x+x2-x
=-2-6x+x2;
(3)(-2)2012×0.125671
=(-2)2012×0.52013
=(-2)2012×0.52012×0.5
=0.5.
| 1 |
| 2 |
=(
| 1 |
| 2 |
=2a4b3x3 ;
(2)-2(1-
| 3x |
| 2 |
| x-1 |
| 4 |
=-2+3x-8x+x(x-1)
=-2+3x-8x+x2-x
=-2-6x+x2;
(3)(-2)2012×0.125671
=(-2)2012×0.52013
=(-2)2012×0.52012×0.5
=0.5.
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