题目内容
把该式分解因式:
x2+x-6
解:原式=(x+3)(x-2)
分析:是x2+(p+q)x+pq型.
4a2-(b-c)2
a2(x-y)+b2(y-x)
x2+x-4y2-2y
1-x2+4xy-4y2
2x2+2xy-3x-3y