题目内容
(1)计算:
-
(2)化简求值:已知|a+
|+(b-3)2=0,求代数式[(2a+b)2+(2a+b)(b-2a)]÷2b的值.
(3)分解因式:2a3-4a2b+2ab2
| x2-y2 |
| x+y |
| 4x(x-y)+y2 |
| 2x-y |
(2)化简求值:已知|a+
| 1 |
| 2 |
(3)分解因式:2a3-4a2b+2ab2
(1)原式=
-
(2分)
=x-y-(2x-y)(3分)
=-x(4分)
(2)由题意,可得a+
=0,b-3=0
解得a=-
,b=3
原式=(2a+b)(2a+b+b-2a)÷2b(2分)
=2a+b
=2×(-
)+3
=2.(4分)
(3)原式=2a(a2-2ab+b2)(2分)
=2a(a-b)2(4分).
| (x+y)(x-y) |
| x+y |
| (2x-y)2 |
| 2x-y |
=x-y-(2x-y)(3分)
=-x(4分)
(2)由题意,可得a+
| 1 |
| 2 |
解得a=-
| 1 |
| 2 |
原式=(2a+b)(2a+b+b-2a)÷2b(2分)
=2a+b
=2×(-
| 1 |
| 2 |
=2.(4分)
(3)原式=2a(a2-2ab+b2)(2分)
=2a(a-b)2(4分).
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